Normal() again

[Alexander Frink]

On Tue, 23 Nov 1999, Do Hoang Son wrote:
> Call expression.normal().normal() could be easiest way.
> if one calls expand() then normal(), it will take long time in case
> his/her expression is long.

Probably one can construct an example where it would be necessary
to call .normal().normal().normal() (and worse) to end up with the
desired result. Also .expand().normal() will probably fail sometimes.
So this looks like a more serious issue...

-- 
Alexander Frink                      E-Mail: Alexander.Frink at Uni-Mainz.DE
Institut fuer Physik                 Phone:  +49-6131-393391
Johannes-Gutenberg-Universitaet
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