patch for expansion of log.

[Jens Vollinga]

Hi.

On Fri, Apr 16, 2004 at 06:03:50PM +0000, Chris Dams wrote:
> 
> Hello,
> 
> I found out that trying to calculate
> 
> 	log(a*x+b*x*x*log(x)).series(x==0,3)
> 
> does not terminate. This is because in the function the argument has a
> pole even if a log(a*x) is subtracted. The attached patch should solve
> this. With this patch the result of the calculation is
> 
> (log(x*a))+(a^(-1)*b*log(x))*x+(-1/2*a^(-2)*b^2*log(x)^2)*x^2+Order(x^3)
> 
> as expected.
> 

Your patch has been applied. Thanks!

Bye, and nice weekend too,
Jens